function diffdate(day1, month1, year1, day2, month2, year2)
local days1 = day1 + month1 * months[month1] + year1 * 365 -- ну следующий високосный год 2020, поэтому можно пренебречь
local days2 = day2 + month2 * months[month2] + year2 * 365
local difference = days1 - days2
local difference = math.abs(difference)
return difference
end
months = {
[01] = 31,
[02] = 28,
[03] = 31,
[04] = 30,
[05] = 31,
[06] = 30,
[07] = 31,
[08] = 31,
[09] = 30,
[10] = 31,
[11] = 30,
[12] = 31
}